Consider the functions f(x) = (4/5)x and g(x) = (4/5)x+6. What are the ranges of the two functions?
f(x): {yly > }
g(x): {yl y > }

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.

i believe that the answer is

b. y-1=-2(x-4)

hope this !

idk wbu

step-by-step explanation: