Below is the graph of a trigonometric function. It has a maximum point at
(−π3,2)\left(-\dfrac{\pi}{3},2\righ t)
(−
3

π


,2)
left parenthesis, minus, start fraction, pi, divided by, 3, end fraction, comma, 2, right parenthesis
and an amplitude of
1.81.8
1.8
1, point, 8
.

1\small{1}
1
2\small{2}
2
3\small{3}
3
4\small{4}
4
-1\small{\llap{-}1}
-
1
-2\small{\llap{-}2}
-
2
-3\small{\llap{-}3}
-
3
-4\small{\llap{-}4}
-
4
1\small{1}
1
2\small{2}
2
3\small{3}
3
4\small{4}
4
-1\small{\llap{-}1}
-
1
-2\small{\llap{-}2}
-
2
-3\small{\llap{-}3}
-
3
-4\small{\llap{-}4}
-
4
yy
y
xx
x
(−π3,2){(-\frac{\pi}{3},2)}
(−
3

π


,2)
What is the midline equation of the function?