The number of cameras produces since May at a plant can be modeled by the function N(m)=50m+600 and the cost per camera can be modeled by C(m)=4m^2-15m+45, where m is the number of months since May. According to this model, what is the total amount of revenue generated by the plant's camera production on September?

39200

Step-by-step explanation:

Revenue = number of cameras * cost

R(m) = N(m) * C(m)

        = (50m+600) * (4m^2-15m+45)

The months since may is June July August September = 4 months

R(4) = (50*4+600) * (4*4^2-15*4+45)

        (200+600) * (64-60+45)

           800*49

                39200

39,200

Step-by-step explanation:

September is 4 months after may, so m = 4

No. of cameras:

N(4)=50(4)+600 = 800

Cost per camera:

C(4)=4(4²)-15(4)+45 = 49

Total cost:

N × C

800 × 49

39200

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

ian gonna lie that is way to much