Complete for 11 points.

Arnett - red car

Bradley - gray car

Church - yellow car

Dawson - silver car

Step-by-step explanation:

1st clue - we know that Bradley and Church can't have the silver car.

2nd clue - we know that Dawson can't have the red or gray car.

3rd clue - we know that Dawson and Arnett can't have the yellow car.

Based on the 2nd and 3rd clue, we know Dawson has the silver car because he can't have the red, gray, or yellow car.

4th clue - we know Bradley can't have the red or yellow car.

That leaves us with the gray car for Bradley because he had lunch with the owner of the silver car (which i consider also a bright color but i don't know if that counts).

so far:

dawson - silver car

bradley - gray car

and we know arnett can't have the yellow car because the owner of hte yellow car thinks he got a better car with his car then dawson and arnett, which leaves us with the red car for arnett.

dawson - silver car

bradley - gray car

arnett - red car

by process of elimination, that means church has the yellow car.

arnett - red car

bradley - gray car

church - yellow car

dawson - silver car

Arnett: red car; Bradley: grey car; Church: yellow car; Dawson: silver car.

(See attached image)

Step-by-step explanation:

■The yellow car isn't owned by Bradley (4)

■The yellow car isn't owned by Arnett (3)

■The yellow car isn't owned by Dawson (3)

►Then Church owns the yellow car.

■Dawson's car isn't red or gray (2)

►Then Dawson owns the silver car.

■Bradley's car isn't red (4)

►Then Bradley owns the grey car.

And so:

►Arnett owns the red car.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

dont know

step-by-step explanation: