The state fair is a popular field trip destination. This year the senior class at High School A and the senior class at High School B both planned trips there. The senior class at High School A rented and filled 1 van and 10 buses with 258 students. High School B rented and filled 8 vans and 5 buses with 264 students. Each van and each bus carried the same number of students. How many students can a van carry? How many students can a bus carry?

The van holds 18 students

The bus holds 24 students

Step-by-step explanation:

v = van  b = bus

High School A

1v+10b = 258

High School B

8v+5b = 264

Multiply the second equation by -2

-16v - 10b = -528

Add  this to the first equation

-16v - 10b = -528

1v+10b = 258

-15v      = -270

Divide each side by -15

-15v/-15 = -270/-15

v =18

The van holds 18 students

Now we need to find the number the bus holds

1v+10b = 258

18 + 10b = 258

Subtract 18 from each side

18-18+10b = 258-18

10b=240

Divide each side by 10

10b/10 =240/10

b = 24

The bus holds 24

Van: 18

Bus: 24

Step-by-step explanation:

V + 10B = 258

V = 258 - 10B

8V + 5B = 264

8(258 - 10B) + 5B = 264

2064 - 80B + 5B = 264

75B = 1800

B = 24

V = 258 - 10(24) = 18

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation:

what is the question?

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