A medical researcher is studying the spread of a virus in a population of 1000 laboratory mice. During any week, there is an 80% probability that an infected mouse will overcome the virus, and during the same week there is a 10% probability that a noninfected mouse will become infected. Three hundred mice are currently infected with the virus. How many will be infected next week and in 3 weeks

The number of mice that will be infected next week are 130 while

The number of mice that will be infected in 3 weeks are 111

Step-by-step explanation:

From the information given , the researcher is studying the spread of a virus in a population of 1000 laboratory mice. i.e, n = 1000

Number of infected = 300

Non infected = 1000 - 300 = 700

Probability an infected mouse will overcome = 80% = 0.8

Probability a noninfected mouse becomes infected = 10% = 0.10

The number of infected that will overcome = 0.8 * 300 = 240

The number of non infected that will become infected = 0.1 * 700 = 70

The number that will be infected on the first week =

300 - 240 + 70

= 130

Number that will be healthy on the first week =

700 + 240 - 70

= 870

Calculating for week 2:

The number of infected that will overcome = 0.8 * 130 = 104

The number of non infected that will become infected = 0.10 * 870 = 87

The number that will be infected on the second week =

130 - 104 + 87

= 113

Number that will be healthy on the second week =

870 + 107 - 87

= 887

Calculating for week 3:

The number of infected that will overcome = 0.8 * 113 = 90.4

The number of non infected that will become infected = 0.10 * 887 = 88.7

The number that will be infected on the third week =

113 - 90.4 + 88.7

= 111.3 ≈ 111

Number that will be healthy on the third week =

887 + 90.4 - 88.7

= 888.7 ≈ 889

From our calculations, the number of mice that will be infected next week are 130

The number of mice that will be infected in 3 weeks are 111

15 batches are the most you can make

step-by-step explanation:

the correct option is 2.

step-by-step explanation:

according to the given information triangle abc is a right angle triangle with right angle at a. segment ab is 5 and segment ac is 7. point d is on segment bc and angles adb and adc are right angles.

it is given that triangles abd, cad, and cba are similar.

two triangles are similar if their corresponding sides are proportional.

in triangle cba, using pythagoras theorem

                      )

triangle abd and cba are similar,

                            (2)

triangle cad and cba are similar,

                      )

using (1), (2) and (3), we get

hence proved.

therefore option 2 is correct.