Determine the nth term formula for each of the following sequences and find the limit if it exists.

3, 3,-3, 3,

aₙ = (-3) (-1)ⁿ⁻¹

limit does not exist

Step-by-step explanation:

-3, 3, -3, 3, ...

This is an alternating geometric series where the first term is -3 and the common ratio is -1.  The nth term is therefore:

aₙ = (-3) (-1)ⁿ⁻¹

Since the sequence alternates between -3 and 3, the limit as n approaches infinity of aₙ does not exist.

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hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb