At a storage company, items are stored in containers that have a base of 4 1 5 yds by 1 1 3 yds. If there is a 3 × 3 array of these containers with no space between them, what is the area covered by the containers?

Area = 50.4 yd²

Step-by-step explanation:

Given

Base dimension of container = 4⅕ by 1⅓ yd

Array: 3 * 3 containers without space

Required

Area covered by the containers

First, it'll be assumed that the container has a rectangular base.

The dimension of the base is measured out as follows:

Length, L = 4⅕ yd

Width, W = 1⅓ yd

Note that this can also be interchanged.

Next, is to calculate the area of 1 container..

Area = 4⅕ yd * 1⅓ yd

Convert mixed fractions to improper fraction

Area = 21/5 * 4/3 yd²

Area = 84/15 yd²

Area = 28/5 yd²

Area = 5.6 yd²

Next, is to calculate the area of the 3 by 3 containers.

Given that the container formed a 3 by 3 array;

This means that there 3 * 3 containers

3 * 3 = 9 containers.

Area of the 9 containers = 9 * Area of 1 container.

Area = 9 * 5.6 yd²

Area = 50.4 yd²

Hence, the area covered by the containers is 50.4 yd²

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step-by-step explanation:

answer:

total cost for tiles and paints is $924.  

step-by-step explanation:

we have been given that a community hall is in the shape of a cuboid. the hall is 40m long 15m high and 3m wide.

the paint will be required for 4 walls and ceiling.

let us find area of walls and ceiling.

therefore, the area of walls and ceiling is 1410 square meters.

given: cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. therefore,

therefore, the total painting cost is $564.

tiles will be required for floor. let us find the area of floor.

given: 1m squared floor tiles costs $3. so,

therefore, the total tiles cost is $360.

now let us find combined total cost of tiles and paint.

therefore, the combined total cost of tiles and paint is $924.