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f ( x ) = - 2x^2 + 3x + 1

Step-by-step explanation:

If f ( x ) extends to → − ∞, as x→ − ∞ , provided f(x) → − ∞, as x → +∞, we can rewrite this representation as such;

− ∞  < x < ∞, while y > − ∞

Now the simplest representation of this parabola is f ( x ) = - x^2, provided it is a down - facing parabola;

If we are considering a down - facing parabola, the degree of this trinomial we should create should be even, the LCM being negative. Knowing that we can consider this equation;

Solution; f ( x ) = - 2x^2 + 3x + 1, where the degree is 2, the LCM ⇒ - 2

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204