Line R T is a perpendicular bisector of Line segment U V. Line R T is a perpendicular bisector of line segment U V. The lines intersect at point S. Line segment U S and S V are congruent. What is true of any triangle created by points U, V, and any point on Line R T other than S?

x > 1.3

step by step:

8.5−0.9x> 9.8−1.9x

step 1: simplify both sides of the inequality.

−0.9x+8.5> −1.9x+9.8

step 2: add 1.9x to both sides.

−0.9x+8.5+1.9x> −1.9x+9.8+1.9x

1x+8.5> 9.8

step 3: subtract 8.5 from both sides.

1x+8.5−8.5> 9.8−8.5

1x> 1.3

step 4: divide both sides by 1.

1x/1 > 1.3/1

there is nothing below so i cannot

step-by-step explanation:

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