If sin(x) = square2/2 what is cos(x) and tan(x)

We are given that  s i n ( x ) = 1 2

. We can solve this equation for x by taking the sine inverse of both sides of the equation.

s i n − 1 ( s i n ( x ) ) = s i n − 1 ( 1 2 )

Simplifying the left-hand side gives the following:

x = s i n − 1 ( 1 2 )

Thus, x is the angle, such that  

s i n ( x ) = 1 2 .  

In trigonometry, there are special angles that have well known trigonometric values, and one of these angles is 30°. For an angle of measure 30°, we have the following:

s i n ( 30 ∘ ) = 1 2 c o s ( 30 ∘ ) = √ 3 2

Since  

s i n ( 30 ∘ ) = 1 2 , we have that  

s i n − 1 ( 1 2 ) = 30 ∘ , so x = 30°.  

As we just saw,  c o s ( 30 ∘ ) = √ 3 2

. To find tan(30°), we will use the trigonometric identity that  

t a n θ =s i n θ c o s θ

. Thus, we have the following:

t a n( 30 ∘ ) = s i n ( 30 ∘ ) c o s ( 30 ∘ ) = 1 2 √ 3 2 = 1 2 ⋅ 2 √ 3 = 1 √ 3

We get that  

t a n ( 30 ∘ ) = 1 √ 3

. Thus, all together, we have that if  s i n ( x ) = 1 2 , then  

c o s ( x ) = √ 3 2  and  t a n ( x ) = 1 √ 3

.We are given that  s i n ( x ) = 1 2

. We can solve this equation for x by taking the sine inverse of both sides of the equation.

s i n − 1 ( s i n ( x ) ) = s i n − 1 ( 1 2 )

Simplifying the left-hand side gives the following:

x = s i n − 1 ( 1 2 )

Thus, x is the angle, such that  s i n ( x ) = 1 2 .

In trigonometry, there are special angles that have well known trigonometric values, and one of these angles is 30°. For an angle of measure 30°, we have the following:

s i n ( 30 ∘ ) =1 2 c o s ( 30 ∘ ) = √ 3 2  Since  s i n ( 30 ∘ ) = 1 2 , we have that  s i n − 1 ( 1 2 ) = 30 ∘ , so x = 30°.

As we just saw,  c o s ( 30 ∘ ) = √ 3 2

. To find tan(30°), we will use the trigonometric identity that  t a n θ = s i n θ c o s θ

. Thus, we have the following:

t a n ( 30 ∘ ) = s i n ( 30 ∘ ) c o s ( 30 ∘ ) = 1 2 √ 3 2 = 1 2 ⋅ 2 √ 3 = 1 √ 3

Step-by-step explanation:

n trigonometry, the inverse sine function, denoted as  

s i n − 1 x , is defined as the function that undoes the sine function. That is,  s i n − 1 x  is equal to the the angle, θ, such that  s in θ = x , and  s i n − 1 ( s i n ( θ )) = θ

. We can use this definition to determine the angle that corresponds to a specific sine value

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".