A box of chocolates contains five milk chocolates and six dark chocolates. Mike randomly picks a chocolate and eat it. Then Mike randomly picks another chocolate and eats it. Determine the probability Mike eats two milk chocolates. Round to the hundredths place.
Group of answer choices

0.182

0.854

0.133

0.333

0.182.

Step-by-step explanation:

There are a total of 11 chocolates in the box.

Prob(First chocolate picked is milk) = 5/11.

Prob(Second chocolate picked is milk) = 4/10 = 2/5.

So the required probability = 5/11 * 2/5

= 10/55

= 0.182.

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

$4034.40

the perimeter of the field is the sum of the lengths of the four sides:

47 yd + 158 yd + 47 yd + 158 yd = 410 yd

the cost of 3 ft (1 yd) of fence is 3×$3.28 = $9.84.

so the cost of jake's wood perimeter fance is

(410 yd) × ($9.84 /yd) = $4034.40