Reasoning in a laboratory, the probability a bacterial colony thrives is 70%. The numbers 0 to 6 represent the outcome that a colony thrives. The numbers 7 to 9 represent the outcomes that a colony does not thrive. The list of random numbers simulates the out comes of 4 colonies . Based On the simulation in 6 trails . what is the probability that exactly half of the colonies will thrive.
4285 6903 3829 7871 2868 5137

The probability that exactly half of the colonies will thrive = (1/3) = 0.3333

Step-by-step explanation:

The list of random numbers simulates the out comes of 4 colonies.

Based On the simulation in 6 trails, what is the probability that exactly half of the colonies will thrive?

The probability of an event is given mathematically as the number of elements in the event divided the total number of elements in the sample space.

Noting that the numbers 0 to 6 indicate that a colony thrives and the number 7 to 9 represent that a colony doesn't thrive.

The 6 trials are given as

4285; 3 colonies thrive, 1 doesn't.

6903; 3 colonies thrive, 1 doesn't.

3829; 2 colonies thrive, 2 don't.

7871; 1 colony thrives, 3 don't.

2868; 2 colonies thrive, 2 don't.

5137; 3 colonies thrive, 1 doesn't.

The number of trials where exactly 2 colonies thrive = 2

The total number of trials = 6

The probability that exactly half of the colonies will thrive = (2/6) = (1/3) = 0.3333

Hope this Helps!!!

i may be incorrect but i believe that her first error was in step one when she multiplyed her equation by 1/4 when she should have divided it by 1/4