Find the middle term of the expansion of (x+y)^8 a40x^2y^2 b70x^2y^2

the middle term = 70x⁴y⁴

Step-by-step explanation:

Given;

(x+y)⁸

This expression can be expanded as follows, using Paschal triangle;

                                                 1      1

                                               1    2     1

                                             1     3      3      1

                                         1     4       6      4     1

                                    1       5     10    10       5    1

                            1           6      15     20     15     6        1

                    1            7         21      35     35      21     7          1

        1                 8          28        56     70     56    28       8         1

At level 8, the middle coefficient is 70

Also the power of x and y will be equal in the middle term = A(xⁿ yⁿ)

A = 70 ,

n +n = 8

n = 4

Thus, the middle term = 70x⁴y⁴

d, x=8

step-by-step explanation:

simplifying

4x + -5 = 2x + 11

reorder the terms:

-5 + 4x = 2x + 11

reorder the terms:

-5 + 4x = 11 + 2x

solving

-5 + 4x = 11 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-5 + 4x + -2x = 11 + 2x + -2x

combine like terms: 4x + -2x = 2x

-5 + 2x = 11 + 2x + -2x

combine like terms: 2x + -2x = 0

-5 + 2x = 11 + 0

-5 + 2x = 11

add '5' to each side of the equation.

-5 + 5 + 2x = 11 + 5

combine like terms: -5 + 5 = 0

0 + 2x = 11 + 5

2x = 11 + 5

combine like terms: 11 + 5 = 16

2x = 16

divide each side by '2'.

(23*2)-12=x     x=34

step-by-step explanation: