Find the middle term of the expansion of (x+y)^8 a40x^2y^2 b70x^2y^2

the middle term = 70x⁴y⁴

Step-by-step explanation:

Given;

(x+y)⁸

This expression can be expanded as follows, using Paschal triangle;

                                                 1      1

                                               1    2     1

                                             1     3      3      1

                                         1     4       6      4     1

                                    1       5     10    10       5    1

                            1           6      15     20     15     6        1

                    1            7         21      35     35      21     7          1

        1                 8          28        56     70     56    28       8         1

At level 8, the middle coefficient is 70

Also the power of x and y will be equal in the middle term = A(xⁿ yⁿ)

A = 70 ,

n +n = 8

n = 4

Thus, the middle term = 70x⁴y⁴

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

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