Dilate line f by a scale factor of one half with the center of dilation at the origin to create line f'. Where are points A' and B' located after dilation, and how are lines f and f' related?

The locations of A' and B' are A' (0, 2) and B' (0, 0); lines f and f' intersect at point A.

The locations of A' and B' are A' (0, 1) and B' (1, 0); lines f and f' are parallel.

The locations of A' and B' are A' (0, 0) and B' (2, 0); lines f and f' intersect at point B.

The locations of A' and B' are A' (0, 2) and B' (2, 0); lines f and f' are the same line.

Option (2).

Step-by-step explanation:

The given graph is for a line 'f' having points A(0, 2) and (2, 0).

Rule for dilation of point (x, y) by a scale factor 'k' about the origin is,

(x, y) → (kx, ky)

By this rule, when line segment AB is dilated by a scale factor new points will be,

A(0, 2) → A'(0, 1)

B(2, 0) → B'(1, 0)

By joining these points we can get the new line f'. This line will be parallel to the line 'f'.

Option (2) will be the correct answer.

no this is a nonlinear negative

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: