Find the first four iterates of the function A(z) = z2 +2+ 21 with an initial value of z^0=1+2t,
-1 + 21, - 1 + 61, -1- 101
b. -1 -21, -1- 11, 991 - 101,- 331
-1 -21, - 1+61, -33-101,991 + 2
d. -1 -21, - 1 + 61, - 33 - 101, 991 +6621
C.

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

where are the graphs?

step-by-step explanation:

the answer is:

the lateral area is equal to

to find the lateral area of the square pyramid, first we need to find the perimeter of the base, and then, find the lateral area using the following formulas:

where,

s, is the base length

slant height, is the height of a the side of the pyramid

we are given:

now, calculating the perimeter of the base, we have:

then, calculating the lateral area:

hence, we have that the lateral area is equal to

have a nice day!