If y varies directly as x, and y is 48 when x is 6, which expression can be used to find the value of y when x is 2?

y = StartFraction 48 Over 6 EndFraction (2)

y = StartFraction 6 Over 48 EndFraction (2)

y = StartFraction (48) (6) Over 2 EndFraction

y = StartFraction 2 Over (48) (6) EndFraction

h who knows

step-by-step explanation:

i think it is 70

step-by-step explanation:

ddd

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)