It is possible to approximate the outside temperature based on how fast crickets are chirping. Suppose on a 50 degree day, you measure 52 chirps in a minute, and on a 74 degree day, you measure 148 chirps in a minute.

1. Based on this data, determine a linear equation that will output the number of chirps in a minute, n, given the temperature in degrees, t.

Linear equation n = 4t-148

Step-by-step explanation:

we have to find the equation, that's why we select the data

(t, n) = (50, 52) and (14,148)

we look as follows

n-52 = ((148-52) / (14-50)) * (t-50)

We perform the indicated operations

n-52 = (96/24) * (t-50)

n-52 = 4 (t-50)

finally we get the result

n = 4t-148

30 miles

step-by-step explanation:

we know that 60 seconds equals 1 minute and 60 minutes 1 hour

44 ft       60 sec     60 min     158400   ft

  *   *   =

1 sec       1 min       1 hour         hour

we know that there are 5280 ft per mile

158400   ft       1 mile         30 miles

  *   =

1   hour               5280 ft     1 hour

so in 1 hour   it can travel 30 miles