The diagram shows a track composed with a semicircle on each end. The area of the rectangle is 8,400 square meters. What is the perimeter of the th rack? Use 3.14 for pi

468.4 meters

Step-by-step explanation:

Find the width of the rectangle.

The area of a rectangle is A=length*width. Substitute the values of length and area and solve for width.

A=length*width

8,400=140*width

60= width

Use the width of the rectangle to find the circumference of the semicircles. Since each semicircle is half of a circle, the perimeter of the two semicircles is equal to the circumference of one circle.

The circumference of a circle is equal to pid, where d is the diameter. The diameter of the semicircle is the same as  the width of the rectangle.

So, the diameter is 60 meters. Substitute the diameter into the formula for the circumference and simplify using 3.14 for pi.

≈188.4

(2 times 140)+ 188.4

So, the perimeter of the track is 468.4 meters.

the translated point is (5,2)