Divide the polynomials.
The form of your answer should either be p(x)p(x)p, left parenthesis, x, right parenthesis or p(x)+\dfrac{k}{x+1}p(x)+
x+1
k

p, left parenthesis, x, right parenthesis, plus, start fraction, k, divided by, x, plus, 1, end fraction where p(x)p(x)p, left parenthesis, x, right parenthesis is a polynomial and kkk is an integer.
\dfrac{3x^3+x-11}{x+1}=
x+1
3x
3
+x−11

=start fraction, 3, x, cubed, plus, x, minus, 11, divided by, x, plus, 1, end fraction, equals

Step-by-step explanation:

We want to determine the result of the quotient:

We follow the procedure of long division which is set out int he table below.

Therefore:

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.