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3 yd
4 yd
What is the length of the hypotenuse?

5 yd

Step-by-step explanation:

we can use this formula

leg^2+leg^2= hypotenuse ^2

if you plug it in, it should look like this, (let x be the hypotenuse since we are trying to find it)

3^2 + 4^2= x^2

so if you square it, it  should look like this

9+16= x^2

then its

25=x^2

we have to bring the square to the other side, so in order to get rid of it we have to put a radical on top of 25

then you have to find two of the same numbers that times to equal 25 which is 5

so x=5

area of part 1:

a1=base*height/2=(8+2)*(8-2-2-1)/2=10*3/2=15 ft^2

area of part 2:

a2=length*width=(8+2)*1=10 ft2

area of part 3:

a3=length*width=8*2=16 ft2

total shaded area : a1+a2+a3=41 ft2

total area of the reactangle : a=16*8=128 ft2

total area of the nonshaded region : 128-41=87 ft2

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step-by-step explanation: