Celebration is being held honoring five award winners of different ages each winner will be called one at a time in random order what is the probability that the winners will be called in order by the age from youngest to oldest?

1 in 120 or 0.83%

Step-by-step explanation:

There are 5 possible winners to be called first, 4 possible winners are then left to be called second, 3 to be called third, 2 to be called fourth and the final winner is left to be called last. Therefore, the number of possible ways to arrange the winners is:

There is only one possible order for which the winners are called in order by the age from youngest to oldest. Therefore, the probability of this happening is 1 in 120 or 0.83%.

9 x 8 divided by (5-3)=36

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step-by-step explanation: