If you horizontally shift the absolute value parent function, F(x) = |x|, left three
units, what is the equation of the new function?
O A. G(x) = |x+3|
O B. G(X) = |x|-3
C. G(x) = |x-3|
D. G(X) = |x| + 3

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step-by-step explanation:

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i know the way

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57.09 minus 7.0435 equals

step-by-step explanation:

just subtrach them both and u get the answer of 50.0465

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen