G To the right are the outcomes that are possible when a couple has three children. Assume that boys and girls are equally likely, so that the eight simple events are equally likely. Find the probability that when a couple has three children, there is exactly 1 boy. 1st 2nd 3rd boy minus boy minus boy boy minus boy minus girl boy minus girl minus boy boy minus girl minus girl girl minus boy minus boy girl minus boy minus girl girl minus girl minus boy girl minus girl minus girl What is the probability of exactly 1 boy out of three children?

3 in 8 or 37.5%

Step-by-step explanation:

It is know that the sample space for the event of having three children has 8 possible outcomes. In order to have EXACTLY one boy, either the first children is a boy and the other two are girls, the second one is a boy and the other two are girls, or the first two are girls and the last children is a boy.

Therefore, there is a 3 in 8 probability that the couple will have exactly one boy:

The probability is 3 in 8 or 37.5%.

the probability of getting a boy is out of three children is  

Step-by-step explanation:

Given That,

1st                 2nd                   3rd

Boy              Boy                   Boy

Boy              Boy                   Girl

Boy              Girl                   Boy

Boy              Girl                   Girl

Girl              Boy                   Boy

Girl              Boy                   Girl

Girl              Girl                   Boy

Girl              Girl                   Girl

Probability occur of an event (A) is define as

A is the event of getting 1 boy out of three children

here there are total possible outcomes = 8

number of favourable outcomes of 1 boy =3

hence,

probability = favourable outcome/total outcome

Therefore, the probability of getting a boy is out of three children is  

the y will be in still but your answer will be y x 3

step-by-step explanation:

jk: )

y > 1/3x

y < = -x + 4

hope this : )