Luca wants to keep his collection of 850 ants in either the square container below or the circular one. How much greater would the ant density, in ants per square inch, be in the circular container than the square container? Round your answer to the nearest tenth.

The attachment shows the square and circular containers.

Circular container is 2.3 ants/in² gretaer than square container.

Step-by-step explanation: The image bellow shows a square with sides of 10 inches and a circle with diameter of 10 in. To calculate the density (ants/square in), the area of each is needed.

Area of Square:

A = length*width

A = 10.10

A = 100

Area of Circle:

The diameter of the circle is 10, so the radius is 5.

A = π.radius²

A = 3.14.5²

A = 78.5

Density for square container:

D =

D = 8.5 ants/in²

Density for circular container:

D =

D = 10.8 ants/in²

Comparing both:

10.8 ants/in² - 8.5 ants/in² = 2.3 ants/in²

The circular container is 2.3 ants/in² greater than the square one.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

i think the answer is a p = 78

step-by-step explanation:

there are 6 sides of a hexagon, multiply 13 x 6