Referring to the table below, what's the probability of someone in the survey being either older than 30 or not owning a car?

Denote:

Probability of not owning a car: P(A) = 0.35

Probability of being older than 30: P(B) = 0.6

Probability of not owning a car and being older than 30: P(A⋂B) = 0.21

=> Probability of either not owning a car or being older than 30:

P(A⋃B) = P(A) + P(B) - P(A⋂B) = 0.35 + 0.6 - 0.21 = 0.74

=> Option D is correct

Hope this helps!

:)

d. 74%

Step-by-step explanation:

P(>30) + P(no car) - P(both)

0.60 + 0.35 - 0.21

0.74 × 100

74%

i am thinking c. sorry if im wrong .

step-by-step explanation:

my answer is$ 12

step-by-step explanation:

because 15 -2=12