May 26, 2:15:28 PM
A bag contains 7 red marbles, 3 blue marbles and 8 green marbles. If three marbles
are drawn out of the bag, what is the probability, to the nearest 10th of a percent, that
all three marbles drawn will be green?

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attempt i out of 2

6.9%

Step-by-step explanation:

7 red marbles, 3 blue marbles and 8 green marbles = 18 marbles

P ( green ) = green/total = 8/18 = 4/9

Keep marble

7 red marbles, 3 blue marbles and 7 green marbles = 17 marbles

P ( green ) = green/total = 7/17

Keep marble

7 red marbles, 3 blue marbles and 6 green marbles = 16 marbles

P ( green ) = green/total = 6/16 = 3/8

P (green,green,green)  = 4/9*7/17 * 3/8 = 7/102

To the nearest tenth of a percent

.068627451 = 6.8627451% = 6.9%

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.