A soup bowl is in the shape of a hemisphere with a diameter of 10 cm. What is the approximate maximum volume of soup that the bowl can hold?

3.48cm³ (approximated)

Step-by-step explanation:

The maximum water that bowl can hold = The volume of the bowl

Radius is half of diameter.

Given -

From the given data we can derive that the radius of the hemispherical bowl is 5cm (10/2)

Putting the known values into the formula to get the value of the volume of bowl :

= 3.48888cm³

= 3.48cm³

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

28

step-by-step explanation:

because that's the answer