What are the x- and y-intercepts for a line with one point at (2,1) and another at (6,3)?

x - intercept = 0 and y - intercept = 0

Step-by-step explanation:

Using the two point slope intercept form, the formula is;

(y - y1)/(x - x1) = (y2 - y1)/(x2 - x1)

We are given the intercepts to be at

(2,1) and (6,3).

So, x1 = 2 and x2 = 6,while y1 = 1 and y2 = 3

Plugging into the equation, we have;

(y - 1)/(x - 2) = (3 - 1)/(6 - 2)

(y - 1)/(x - 2) = 2/4

(y - 1)/(x - 2) = 1/2

Cross multiply to get;

2(y - 1) = x - 2

2y - 2 = x - 2

2y = x

Now, the x intercept will occur at y = 0.

Thus,

2(0) = x

x = 0

Also, the y intercept occurs when x = 0.

So, 2y = 0

y = 0

x - intercept occurs at (0,0) and y - intercept occurs at (0,0)

answer: y = -12x + 108

step-by-step explanation: do (y = m x+b) formula.

what is the answer?