(x – 3)^2 + (y + 6)^2 = 16

the radius of the circle is ?

The center is (3, -6) and the radius is 4

Step-by-step explanation:

(x – 3)^2 + (y + 6)^2 = 16

We can write the equation of a circle as

(x – h)^2 + (y -k)^2 = r^2

Where (h,k) is the center and r is the radius

(x – 3)^2 + (y -  -6)^2 = 4^2

The center is (3, -6) and the radius is 4

4

Step-by-step explanation:

By comparing with the canonical form of the equation of a circle

(X-Xo)^2 + (Y-Yo) ^2 = r^2; Xo and Yo are the coordinates of the centre of the circle

r^2= 16 >> r = 4

answer: the angel abc is 30°,and the abc is a triangle where the angel bac is 90°

so ac is the half of 24=12ft,and from the pythagorean theorem we find ba

ba=√bc^2-ac^2=√576-144=√432=12√3ft

so bac is 12+12√3=12(1+√3)ft

add them

step-by-step explanation:

idk you did not give the options or numbers so you cant solve it