An object is thrown off a platform that is 15 ft high with an initial velocity of 8.5 ft/is what function models the height h of the object after t seconds

Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".

Step-by-step explanation:

Since the object has a initial velocity and it's being accelerated by gravity, than it's height is defined by:

H(t) = H(0) + V(0)*t + 0.5*g*t²

Applying the data from the problem, we have:

H(t) = 15 + 8.5*t + 0.5*32.17405*t²

H(t) = 15 + 8.5*t + 16.09*t²

Therefore the function that models the height of the object after t seconds is given by "H(t) = 15 + 8.5*t + 16.09*t²".

step-by-step explanation:

from the graph attached below:

domain of graph is the value of x for which the given function profit function p(x) is defined.

(a) the domain represents the number of years for which the outlet will earn a profit.

range of profit function defines the lowest to highest value of profit earned.

(b) the range of this function is (0 , 160 ). for this function, the range represents the outlet's profit earned.

c

step-by-step explanation: