Pls help quick!

A satellite orbiting Earth at an orbital radius r has a velocity v. Which represents the velocity if the satellite is moved to an orbital radius of 5r?(1 point)

15√v

1

5

v

15v

1

5

v

5√v

5

v

5v

v / √5

Step-by-step explanation:

Solution:-

- We have a satellite of mass ( m ) that orbits the earth of mass ( M ). The radius of orbit is ( r ) : center of earth - to - center of satellite radial distance.

- The satellite orbits the Earth with constant tangent velocity ( v ). The velocity  ( v ) is a function of massive body ( M ) about which the smaller body orbits and orbital radius ( r ).

- The formulation is given by:

Where,

          G: The universal gravitational constant

- We are to compare the orbital speeds by changing some of the parameters in the above relation.

- The effect on the orbital speed ( v_orbit ) by increasing the orbital radius to ( 5r ) can be evaluated using the given relation. Such that:

- Now take the ratio of initial orbital speed to the increased orbital radius ( 5r ):

(d)

step-by-step explanation:

given: the line in the graph passes through points (5,30) and (6,26).

then, the equation of line is:

now, put y=a(n) and x=n,

hence, option d is correct.

geometry: triangles

solvers

lessons

answers archive

call the larger triangle abc

then the smaller triangle cde is similar to abc (all angles are equal, aaa).  

ab is the side that is 36, and we wish to find de, the side corresponding to ab

area_cde = area_abc - area_cde --> area_abc / area_cde = 2

let x=length of de

ratio of areas = (ratio of sides)^2

+2+=+%2836%2fx%29%5e2+

+2+=+1296%2fx%5e2+

++x%5e2+=+1296%2f2+=+648+

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