The graphed line shown below is y = negative 4 x minus 12.

On a coordinate plane, a line goes through (negative 3, 0) and (negative 2, negative 4).

Which equation, when graphed with the given equation, will form a system that has no solution?
y = 4 x + 12
y = negative 4 x
y = negative 12
y = negative 4 (x + 3)

Which equation, when graphed with the given equation, will form a system that has an infinite number of solutions?

y + 1 = 3 x

y = negative 3 x + 1

y = 3 x + 1

y minus 3 x = negative 3

Mark this and return

Step-by-step explanation:

can you complete your sentence? i could !

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west