First answer that is CORRECT WILL get Brainliest. Don’t answer if you don’t know. I don’t want what you think or any guesses. I want what you KNOW! I apologize if I come off as rude, I’m on limited time here.

Hints- Think about how to move components of the figure on the left so that the dimensions match those of the rectangle on the right. The total area of the left cannot change when moving the components.

Thank you in advanced

d

gimmee one of those gold crowns!

~coco

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

do your own work and don"t cheat.

step-by-step explanation:

what is the question? i am guessing you are looking for the area.

to find an area, you have to do length x width.

in this case, it would be 12 ft x 4 ft = 48 sq. ft