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Mark charged a battery. Each minute, the percentage of the battery's capacity that was charged increased by 2.5 percent. After 17 minutes of charging, the battery was 61.5 percent full.

How full was the battery when the charging began?

How long from the time that Mark started charging did it take the battery to be fully charged?

original charge=21/5%

time to full charge=32.4 min

Step-by-step explanation:

an=a+(n-1)d

61.5=a+(17-1)(2.5)

61.5=a+40

a=61.5-40=21.5

original charge=21.5 %

100=21.5+(n-1)(2.5)

100-21.5=(n-1)(2.5)

78.5=(n-1)(2.5)

n-1=(78.5)/2.5=15.7/0.5=31.4

n=31.4+1=32.4

idk

step-by-step explanation:

answer:   35 % is the probability of a late departure or an early arrival.

step-by-step explanation:

let l represents the late departure and e represents the early departure.

then, according to the question,

p(l) = 12 %,   p(e) = 27 % and = 4 %

and, we have to find out,

but, we know that,

which is the required equation that will use to find the probability of a late departure or an early departure.

therefore,   the probability of a late departure or an early arrival =   35 %