In ΔCDE, the measure of ∠E=90°, DC = 5, CE = 4, and ED = 3. What ratio represents the sine of ∠C?

The sine of an angle in a right triangle is the ratio of the side opposite to

the angle to the hypotenuse side.

Reasons:

The given parameters of ΔCDE are;

∠E = 90°, DC = 5, CE = 4, ED = 3

Required: The ratio that represents the sine of ∠C

Solution:

Given that ∠E = 90° therefore;

ΔCDE is a right triangle

DC = The hypotenuse side = 5

ED = 3 = The side opposite ∠C

Therefore;

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As E is right angle , CD is hypotenuse , and ED is perpendicular and CE is the base .

Thus sinC = Perpendicular/ Hypotenuse

sinC = ED/CD

sinC = 3/5

good luck on your studies! : )

david edward.

one peck is 9.309 quarts

9.309x 2