Which point is NOT part of the solution of the inequality y < |3x| + 1? (2, –9) (0, 0) (3, 15) (–4, 12)

I think it would be (2,-9)

Step-by-step explanation:

I got three solutions which were:

( 0 , − 1 ) , ( 1 , 2 ) , ( 2 , 5 )

I'm not sure how you could get (2, –9) (0, 0) (3, 15) (–4, 12)

But, based on random logic of mine 2,-9 is the wrong one.

homozygous. one is homozygous, while two is heterozygous.

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2