A circle is centered at N (-6, -2). The point E (-1, 1) is on the circle. Where does point H (-10, -7) lie?

inside circle
on circle
outside circle

  outside circle

Step-by-step explanation:

The difference E -N is ...

  E -N = (-1-(-6), 1-(-2)) = (5, 3)

The difference H -N is ...

  H -N = (-10-(-6), -7-(-2)) = (-4, -5)

The length of line HN will be √(4² +5²), which is a larger number than the length of line EN, which is √(5² +3²).

H lies outside the circle.

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )

i dont know sorry

step-by-step explanation: