If the data in the table were entered into a regression calculator to produce a scatterplot and trend line, which window size would display all the points? x y 2 5 5 16 6 20 10 29 12 36 17 53 0 less-than-or-equal-to x less-than-or-equal-to 20; 0 less-than-or-equal-to y less-than-or-equal-to 50 0 less-than-or-equal-to x less-than-or-equal-to 20; 0 less-than-or-equal-to y less-than-or-equal-to 60 0 less-than-or-equal-to x less-than-or-equal-to 50; 0 less-than-or-equal-to y less-than-or-equal-to 20 0 less-than-or-equal-to x less-than-or-equal-to 60; 0 less-than-or-equal-to y less-than-or-equal-to 20

  0 less-than-or-equal-to x less-than-or-equal-to 20;

  0 less-than-or-equal-to y less-than-or-equal-to 60

Step-by-step explanation:

The range in values of x is from 2 to 17, so a suitable window would be 0 to 20.

The range in values of y is from 5 to 53, so a suitable window would be 0 to 60.

  0 ≤ x ≤ 20

  0 ≤ y ≤ 60

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

a. -0.3 > -0.33