Point B has coordinates (2,1). The x-coordinate of point A is negative 1. The distance between point A and point B is 5 units. What are the possible coordinates of point A?

(-1, 5)

(-1, -3)

Step-by-step explanation:

Given that coordinates of point B = (2,1) this means, x2 = 2 & y2 = 1.

The x coordinate of point A = -1

D = 5 units

Let's use the equation for distance between points, it is expressed as:

Solving further, let's square both sides,

Solving further, we have:

For the possible values, we have:

Therefore, the possible coordinates of point A are:

(-1, 5)

(-1, -3)

2 apples

step-by-step explanation:

taking away equals subtraction. 6-4=2