A parabola has its vertex at ( 3 , − 1 )and passes through the point ( 1 , 7 ). A second parabola has its vertex at ( 1 , 4 ) and has a y-intercept of 3. Write and algebraically solve a system of equations that represents this situation.

step-by-step explanation:

10.50 + taxes which added up to 11.50

step-by-step explanation: 4 cause 2+2=4

(1, –1), (16, –4), (36, –6)

step-by-step explanation:

given that the function is

this can also be written as

we have to graph this function and check which list of points lie on the graph

see attachment for graph:

we find that the points lying are (1,-1) (16,-4) and (36,-6)

since square root is there we find that x can only be posiitve but y can be since square root both positive and negative.

answer:   2 multiplied by x =24

step-by-step explanation: