Please help me I will give you all my points

There are five marbles in a bag. Three are green and two are yellow. You draw a marble, do not replace it, and then draw another. What is the probability of choosing a yellow marble then a green marble?

likely

Step-by-step explanation:

it is likely because at first there were 3 green marbles and three is more than 2 so at the first draw you probably chose a green one but at the second time they are both equal so it's a 50-50 chance

I am assuming you mean that 2 marbles are picked out of the box. Since we have only 2 yellow marbles the solution the your problem would be

P( we pick 2 yellow marbles)

2/5 x 1/4= 0,10

Step-by-step explanation: Mark me as brainliest

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560