Which is the equation of a hyperbola with directrices at x = ±2 and foci at (5, 0) and (−5, 0)?

y squared over 40 minus x squared over 10 equals 1
y squared over 10 minus x squared over 15 equals 1
x squared over 10 minus y squared over 40 equals 1
x squared over 10 minus y squared over 15 equals 1

answer is 8x+24

area of vanessa's patio = length × width

given, length = (3x² + 5x + 10)

width = (x² - 3x - 1)

area of vanessa's patio = (3x² + 5x + 10)(x² - 3x - 1)

= 3x²(x² - 3x - 1) + 5x(x² - 3x - 1) + 10(x² - 3x - 1)

= 3x⁴ - 9x³ - 3x² + 5x³ - 15x² - 5x + 10x² - 30x - 10

= 3x⁴ - 4x³ - 8x² - 35x - 10

hence, expression of vanessa's patio = (3x⁴ - 4x³ - 8x² - 35x - 10)

answer: an 8-foot rope is tied from the top of a pole to a

stake in the ground, as shown in the diagram

below

step-by-step explanation:

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step-by-step explanation: