The temperature of a pot of water was 180.3 degrees, and it cooled at a rate of minus 2.5 degrees per minute. What was the temperature after 20 minutes? How many minutes did it take to cool from 180.3 degrees to 100.3 degrees?

We want to know the temperature after 20 minutes if we replace x =20 we got:

Now we need to find how many minutes did it take to cool from 180.3 degrees to 100.3 degrees, so we can set up the following equation:

And solving for x we got:

Step-by-step explanation:

For this case we can use a lineal model given by:

Where mis the slope and b the initial value so then based on the info provided the model would be:

Where x represent the time and y the temeperature.

We want to know the temperature after 20 minutes if we replace x =20 we got:

Now we need to find how many minutes did it take to cool from 180.3 degrees to 100.3 degrees, so we can set up the following equation:

And solving for x we got:

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.