On a coordinate plane, parallelogram A B C D has points (3, 6), (6, 5), (5, 1), and (2, 2).
What is the area of parallelogram ABCD?

The area is about  13.01.

Step-by-step explanation:

so to do this we need to find the distance between these  points.And we do that by using the Pythagorean rule a^2 + b^2=C^2

(3,6) and (6,5)

3^2  + 1^2 = c^2

c=

(6,5) and (5,1)

1^2 + 4^2=

= 13.038

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!