You spin the spinner, flip a coin, then spin the spinner again. Find the probability of the compound event. Write your answer as a fraction or percent rounded to the nearest tenth.

The probability of not spinning a 5, flipping heads, then spinning a 1 is

The probability of not spinning a 5, flipping heads, then spinning a 1 is 0.08

Step-by-step explanation:

I may assume the spin contains 5 numbers ( plz change and recalculate if the no. of numbers is different)

P(not spinning a 5) = 4/5

P(flipping head) = 1/2

P(spinning 1) = 1/5

P(not spinning a 5, flipping heads, then spinning a 1)= 4/5   *    1/2   *   1/5 = 0.08 = 0.1

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

srry idk

step-by-step explanation: