Determine between which consecutive integers the real zeros of f(x) = 2x - 5x+1 are located.
between 0&1 and 1&2
between 0&1 and 2&3
b. between -1&0 and 2&3
d. between 1&2 and 2&3
a
C.
Please select the best answer from the choices provided
OA
OB
OC
OD

between 0&1 and 2&3

Step-by-step explanation:

(Assuming that f(x) = 2x^2 - 5x + 1)

To solve this question we just need to find the zeros of the function f(x), and we do that by making f(x) = 0 and finding the values of x:

2x^2 - 5x + 1 = 0

Now we can use Bhaskara's formula:

Delta = b^2 - 4ac = 25 - 4*2 = 17

sqrt(Delta) = 4.12

x1 = (5 + 4.12) / 4 = 2.28

x2 = (5 - 4.12) / 4 = 0.22

the zero x1 = 2.28 is between 2 and 3, and the zero x2 = 0.22 is between 0 and 1, so the answer is 'between 0&1 and 2&3'

As the options A, B, C and D are not clear in the question text, you can just mark the option that has this result.

point a is the center of the circle that passes through points e, f, and g and the center of the circle that passes through points x, y, and z.

correct choice is b

step-by-step explanation:

when you calculate the average rate of change of a function, you are finding the slope of the secant line between the two points. for the function the average rate of change from point to point can be calculated as

to find the average rate of change from day 2 to day 10, note that at day 2, 8 houses were sold, so a(2,8) and at day 10, 2 houses were sold, so b(10,2). thus,