Х+6y = 1
2х - Зу = 32

x = 13

y = (-2)

Step-by-step explanation:

х + 6y = 1 and 2х - Зу = 32 are given equations

Step 1:

Name the equation

х + 6y = 1 ...(1)

2х - Зу = 32 ...(2)

Step 2:

From equation (1) we get,

x + 6y = 1

x = 1 - 6y

Step 3:

Put the Value of x = 1 - 6y in equation (2) we get,

2(1 - 6y) - Зу = 32

2 - 12y - 3y = 32

2 - 15y = 32

15y - 2 = - 32

15y = 2 - 32

15y = - 30

y = - 30/15

y = - 2

Step 4:

Then, put the value of y = - 2 in equation (1)

x + 6y = 1

x + 6(-2) = 1

x - 12 = 1

x = 12 + 1

x = 13

Thus, The value of x is 13 and y is (-2)

13 + 6(-2) = 1 i.e., 13 - 12 = 1

2(13) - З(-2) = 32 i.e., 26 + 6 = 32

450

step-by-step explanation:

you get texts and minutes, so why not

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.