When the maximum value in a data set is exchanged for a higher
number, does it change any of the other numbers in the five-number
summary?

It doesn't change any of the other numbers of the five number summary. Only the maximum value of the data set changes, out of the five number summary of the data set.

Step-by-step explanation:

The five number summary of any data set consists of five values which includes

- The maximum value of the data set.

- The minimum values.

- The lower quartile.

- The upper quartile.

- The median.

These values are usually presented together and ordered from lowest to highest: minimum value, lower quartile (Q1), median value (Q2), upper quartile (Q3), maximum value.

Replacing the maximum value with a higher number doesn't change any of the other five number summary as they all position markers, whose values do not change because of changes at one end of the distribution as the positions of the other variables n the dataset are untouched.

This means that, of the five number summary, only the maximum value of the data set changes.

Although, values like the range, mean and standard deviation also change too.

Hope this Helps!!!

1.3 million hoops i believe

1. sometimes

2.   never

3   .08c = 7.50+.05c   250 pages

step-by-step explanation:

1.   sometimes

the theoretical probability of rolling a 1 is 1/6.   perhaps you got really lucky and never rolled a 1   in those 60 times.   your experimental probability is 0.   or perhaps you rolled a 1   20 times.   your experimental probability is 20/60 is 1/3.     it really just depends on how you rolled in that experiment.

2.   never

the probability of the event occurring is 1.   that is being 100 % sure it will happen.   that is the maximum amount of confidence we have.

3.   no customer card cost:   .08 times number of pages

customer card cost:   7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250  

the cost is the same at 250 pages