"The majority of U. S. car owners still buy American cars."
Ideally, what would the sample be in the study that
generated this stat

Question:

The majority of U.S. car owners still buy American cars." Ideally, what would the sample be in the study that generated this stat?

answer choices

a) Everyone in the United States who owns a car

b) Everyone in the United States who owns an American car

c) A randomly selected group of car owners in the U.S.

d) A randomly selected group of Americans who own American cars

A randomly selected group of car owners in the U.S.

Step-by-step explanation:

In this study, we are told the majority of U.S car owners still buy American cars. The sample in the study that generated this stat would be "a randomly selected group of car owners in the U.S".

⬤ Option A is incorrect, because collecting a sample from every car owner in U.S is impossible as the sample size would be rather tool large.

⬤ Option B is also incorrect because just like in option A, the sample size would be too large. Also this does not  take into consideration those who don't use American cars

⬤ Option D is incorrect, this study deals with all car owners in the U.S, not Americans who own American cars. Therefore selecting a sample from Americans who own American cars would be wrong.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.